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Topic 3: Movement Into and Out of Cells

IGCSE Biology (0610) Study Guide
Every cell is a bag of chemicals wrapped in a membrane, and nothing it does matters unless the right substances can get in and the wrong ones can get out. Topic 3 is the physics of being alive: how oxygen reaches a muscle, how water climbs into a root hair, how a plant stands up without a skeleton, and how a root can hoard nitrate a hundred times more concentrated than the soil it grows in. Three processes do all of this — diffusion, osmosis and active transport — and telling them apart, in the exact words Cambridge wants, is worth more marks than almost anything else you will learn this year.

Hi Tara! This is a small topic that behaves like a big one, because examiners come back to it in almost every paper — in gas exchange, in transport in plants, in digestion, in kidneys. There are only three ideas here. Diffusion: particles spread out on their own because they are already moving. Osmosis: the same thing, but for water, across a membrane that lets water through and holds solutes back. Active transport: the cell paying energy to move something the wrong way up a gradient. What makes Topic 3 the biggest mark-loser in the whole first half of the syllabus is not the science — it is three words. Diffusion is net movement, not just movement. Membranes are partially permeable, never “semi-permeable”. And water moves down a water potential gradient, not “towards the solute”. Get those three right and this topic becomes free marks. Let’s build it properly.

3.1 Diffusion ▼
▶  Watch: Diffusion
Opens on YouTube in a new tab. Watch one, then come back and do the Check Yourself questions — watching without testing yourself feels like learning but is not.

The Big Idea: Nothing Is Ever Still

Put a drop of ink in a glass of perfectly still water and come back an hour later. The whole glass is pale blue. Nobody stirred it. No pump moved it. So what did?

Every particle in a liquid or a gas is constantly moving in a random direction, because it has kinetic energy. It travels a tiny distance, collides with something, bounces off in a new direction, and does it again, millions of times a second. That is true of the ink particles and of the water particles alike. Nothing about that motion knows or cares where the ink “should” go.

Now think about the boundary between the crowded ink drop and the clear water beside it. Particles cross that boundary in both directions all the time. But there are far more ink particles on the ink side, so more of them happen to wander out than happen to wander back in. The result, added up over billions of particles, is a steady drift of ink into the water. That drift is diffusion.

diffusion = the net movement of particles down a concentration gradient
Full definition: diffusion is the net movement of particles from a region of their higher concentration to a region of their lower concentration (down a concentration gradient), as a result of their random movement. Where the energy comes from: the kinetic energy of the randomly moving particles themselves. The cell contributes nothing. Diffusion is a passive process. Concentration gradient: a difference in concentration between two regions. “Down the gradient” means from high concentration towards low concentration.
The Word That Is Worth a Mark: NET

Write “diffusion is the movement of particles from high to low concentration” and you have described a one-way stream of particles marching in formation. That is not what happens, and examiners refuse it. Particles move in every direction at once; only the overall balance runs downhill. One word — net — converts a wrong sentence into a right one. Write it every single time.

The same word saves you again at equilibrium. When the ink is evenly spread, particles have not stopped moving — equal numbers now cross in each direction, so the net movement is zero. “The particles stop moving” is a guaranteed lost mark.

The Four Factors — and Only These Four

The syllabus is explicit about which factors you must be able to investigate: surface area, temperature, concentration gradient and distance. Learn them as a set of four, because “state two factors affecting the rate of diffusion” is a routine question and anything outside this list earns nothing.

FactorIncrease it and the rate…WhyWhere it shows up in the exam
Surface areaincreasesmore places for particles to cross at the same timevilli and microvilli, alveoli, root hairs, gill filaments, folded membranes
Temperatureincreasesparticles have more kinetic energy, so they move fasterwhy diffusion is quicker at 37 °C than in a cold pond
Concentration gradientincreasesa bigger difference means a bigger imbalance in random crossingsventilation, blood flow, respiration using oxygen up
Distancedecreasesa random walk over a long path takes disproportionately longeralveolus wall one cell thick, thin leaves, flat worms
Three Up, One Down

Three of the four factors speed diffusion up when you increase them — surface area, temperature, gradient. Only distance is the odd one out and slows it down. If you can remember “three up, one down”, you will never write “a thicker membrane increases the rate” in a hurry.

Surface Area to Volume Ratio — Why Size Is the Enemy

A cell is supplied across its surface but has to keep its whole volume alive. So what matters is not how much surface it has, but how much surface it has per unit of volume — the surface area to volume ratio.

Take a cube of side l. Surface area = 6l². Volume = l³. So the ratio = 6l² ÷ l³ = 6 ÷ l. Every time the object gets bigger, the ratio gets smaller. That single line of algebra explains why Amoeba needs no lungs and an elephant does.

Surface area to volume ratio: small is generous, big is mean Same shape, three sizes. Acid diffusing in from every face has further to go in the big cube. side 1 cm SA 6 cm² · V 1 cm³ ratio 6 : 1 side 2 cm SA 24 cm² · V 8 cm³ ratio 3 : 1 side 3 cm SA 54 cm² · V 27 cm³ ratio 2 : 1 ratio = 6 / l double the side → area × 4 → volume × 8 so ratio halves green dot = centre green/amber/red line = diffusion distance
The classic agar-cube practical in one picture. The small cube decolourises first because it has the most surface for each unit of volume and the shortest distance from surface to centre.
The Trap Inside the Agar Cube Question

“Which cube has the greatest surface area?” — the biggest one, obviously. “Which decolourises first?” — the smallest one. Both are true and they are not contradictory: the big cube has more total surface but vastly more volume to supply, so its ratio is worse. Whenever a question compares sizes, it is asking about the ratio, not the raw area.

Why Diffusion Never Runs Out

Here is a question that catches people out. Oxygen diffuses into a muscle cell from the blood. Why doesn’t the cell just fill up with oxygen until the concentrations match and diffusion stops?

Because respiration keeps using the oxygen up. The concentration inside never gets a chance to rise, so the gradient is permanently maintained and oxygen keeps flowing in. The mirror image works for carbon dioxide: respiration keeps making it, so its concentration inside stays high and it keeps diffusing out.

This is one of the most reusable two-mark answers in the whole syllabus. “Respiration continually uses up the oxygen, so its concentration inside the cell stays low and the concentration gradient is maintained.” It works for photosynthesis and carbon dioxide in a leaf, for oxygen at a gill, for glucose absorption in the gut — anywhere a gradient somehow refuses to disappear.

Importance of Diffusion in Living Things

Some substances move into and out of cells by diffusion through the cell membrane. Oxygen diffuses into a respiring cell and carbon dioxide diffuses out, both across the cell membrane. In a palisade cell in the light, carbon dioxide diffuses in and oxygen diffuses out. The cell wall of a plant cell is fully permeable, so it is the membrane that the particles must cross.

What diffusesWhereWhy the gradient exists
Oxygenalveolus → blood; blood → respiring cell; water → gillrespiration uses oxygen up inside cells
Carbon dioxiderespiring cell → blood → alveolus; air → palisade cell in lightrespiration makes it; photosynthesis uses it up
Digested food (glucose, amino acids)small intestine → bloodblood carries the absorbed food away, keeping its concentration low
Urealiver cell → bloodthe liver keeps making it; the kidney keeps removing it
Water vapourleaf air spaces → outside air (transpiration)the air outside is usually drier
Worked Example 1 Three cubes of agar containing a pink indicator have sides of 10 mm, 20 mm and 30 mm. They are dropped into an excess of dilute acid at the same time. Calculate the surface area to volume ratio of each, and explain which becomes completely colourless first. [4]
Step 1: Do the arithmetic before you do the biology
Cube of side l: surface area = 6l², volume = l³.
10 mm: 600 mm² ÷ 1000 mm³ = 0.6 : 1
20 mm: 2400 mm² ÷ 8000 mm³ = 0.3 : 1
30 mm: 5400 mm² ÷ 27 000 mm³ = 0.2 : 1
Step 2: Two factors, not one
The 10 mm cube wins twice over. It has the largest surface area to volume ratio, so there is more surface for each unit of volume that has to be reached. And the distance from surface to centre is only 5 mm, against 15 mm for the big cube — and rate of diffusion falls as distance increases.
Step 3: The answer, written the way the mark scheme wants it
“The 10 mm cube becomes colourless first. It has the largest surface area to volume ratio (0.6 : 1), so more acid can enter per unit of volume, and the acid has the shortest distance (5 mm) to diffuse to the centre.”
Ratios 0.6 : 1, 0.3 : 1 and 0.2 : 1; the smallest cube decolourises first because of its larger surface area to volume ratio and shorter diffusion distance.
Worked Example 2 A student measures the time for a coloured solution to diffuse 20 mm through agar at four temperatures: 48 min at 10 °C, 36 min at 20 °C, 27 min at 30 °C and 20 min at 40 °C. State the conclusion and explain it. Then state one thing you cannot conclude. [4]
Step 1: Convert “time” into “rate” in your head
Shorter time means faster diffusion. The times fall from 48 to 20 minutes, so as temperature rises the rate of diffusion increases. Quote figures — a description mark almost always needs numbers.
Step 2: The explanation is always the same sentence
Higher temperature means the particles have more kinetic energy, so they move faster and spread out more quickly. Do not say the gradient got steeper — heating adds no extra particles, so the gradient is unchanged.
Step 3: The evaluation mark — what the data do not say
You cannot conclude that the rate doubles every 10 °C (48 → 36 is nowhere near a doubling of rate), and you cannot say anything about temperatures outside 10–40 °C. Extrapolating past the data is one of the easiest evaluation marks to earn and one of the most commonly thrown away.
Rate increases with temperature because particles gain kinetic energy and move faster; you cannot conclude the pattern continues outside the range tested.

Planning a Diffusion Investigation

Basic method. Make agar containing an indicator, for example phenolphthalein with a little sodium hydroxide, so the agar is pink. Cut cubes with a sharp knife and a ruler. Put each cube into a beaker of dilute hydrochloric acid and time how long it takes for the whole cube to go colourless. The acid diffuses in and the colour disappears.

  • Independent variable: the factor you change. Dependent variable: the time taken to go colourless (rate = 1 ÷ time). Controlled variables: keep the other factors the same.
  • Surface area: cubes of side 1 cm, 2 cm and 3 cm, in the same concentration, volume and temperature of acid.
  • Temperature: identical 1 cm cubes in acid held in water baths at 20, 30, 40 and 50 °C, with the same concentration and volume of acid.
  • Concentration gradient: identical 1 cm cubes in acid of 0.25, 0.50 and 1.00 mol dm⁻³, with the same volume and temperature.
  • Distance: time how long the colour takes to disappear from the surface to the centre of cubes of different sizes, or measure how far the colour change has moved into a long block of agar every minute.
  • Repeat each condition three times and calculate a mean. Use a large volume of acid, so that its concentration hardly falls during the experiment.
Worked Example 7 Identical 1 cm agar cubes are placed in acid of 0.25, 0.50 and 1.00 mol dm⁻³. They take 400 s, 200 s and 100 s to go colourless. Calculate the rates and explain the results. [3]
Step 1: Rate = 1 ÷ time
1 ÷ 400 = 0.0025 s⁻¹; 1 ÷ 200 = 0.0050 s⁻¹; 1 ÷ 100 = 0.0100 s⁻¹.
Step 2: Describe, with figures
As the concentration doubles, the time halves and the rate doubles: from 0.0025 s⁻¹ at 0.25 mol dm⁻³ to 0.0100 s⁻¹ at 1.00 mol dm⁻³.
Step 3: Explain
The higher the concentration, the steeper the concentration gradient, so there is a greater net movement of acid particles into the cube each second.
Rate increases as concentration increases (with figures) [1]; steeper concentration gradient [1]; greater net movement of acid particles into the cube per second [1].
🌿 Apply It: Diffusion in the Real World
Five situations where the four factors decide whether an organism lives or dies. Read the scenario, decide your answer, then open the card.
1
A flatworm in a stream in Coorg is 12 mm long, 6 mm wide and just 0.4 mm thick. It has no lungs, no gills, no heart and no blood. Beside it, a fish of similar mass has all four.
Why can the flatworm survive on diffusion alone when the fish cannot?
▼
Thinness is the whole trick
Being flat means no cell is more than about 0.2 mm from the surface. Diffusion is extremely efficient over such distances, so oxygen reaches every cell without help. The fish is thick, so its innermost cells are centimetres from the water — hundreds of times further, and diffusion time rises steeply with distance.
And the ratio helps too
A flat body has a large surface area to volume ratio: plenty of skin for the amount of respiring tissue. Flattening is nature’s way of getting bigger without getting thicker — which is also why leaves are flat, and why the alveoli and villi are folded.
Biology Connection
Every gas exchange surface you will ever meet in this course — alveolus, gill filament, leaf, root hair, insect tracheole — is designed around the same two factors: maximise surface area, minimise distance. Once you see that, you can predict the adaptations of an organism you have never met.
2
A doctor in Mumbai explains that in pneumonia, fluid collects in the alveoli and their walls become inflamed and thickened. The patient is breathless even though the air around them contains the normal 21 % oxygen.
Which factor affecting diffusion has changed, and why does more oxygen in the room not fix it?
▼
Distance has increased
Oxygen now has to cross fluid plus a thickened wall instead of a single thin cell layer. Rate of diffusion falls as distance increases, so less oxygen reaches the blood per second even though the gradient is unchanged.
Why oxygen therapy still helps — a bit
Giving the patient oxygen-enriched air raises the concentration in the alveolus, which steepens the concentration gradient and partly compensates for the longer distance. It attacks a different factor to offset the damaged one. It cannot make the wall thin again, which is why severe cases need more than oxygen.
Biology Connection
This is the four factors used as a diagnostic tool. If one factor gets worse, you can sometimes rescue the rate by improving another — exactly the logic behind oxygen masks, and behind a fish opening its mouth wider in warm, oxygen-poor water.
3
A biology technician sets up two identical beakers of still water, one at 5 °C and one at 40 °C, and drops an identical crystal of purple dye into each. A student predicts that only the warm beaker will end up evenly coloured.
Is the prediction right? What exactly does temperature change?
▼
Temperature changes the speed, not the destination
Both beakers end up completely evenly coloured. Random movement always produces an even distribution eventually, because there is nothing to stop it. What temperature changes is how quickly equilibrium is reached, because warmer particles carry more kinetic energy.
And at equilibrium, nothing has stopped
Even when the colour is perfectly even, dye particles are still crossing every imaginary boundary in the beaker — just equally in both directions. The net movement is zero. Saying “the particles stop” is the single most common wrong sentence in this topic.
Biology Connection
This is why a fish in a warm pond is in more trouble than a fish in a cold one, but not for the reason most people give: warm water speeds diffusion up, but it also holds far less dissolved oxygen, so the gradient collapses. Two factors pulling in opposite directions.
4
A student sets up a model gut: Visking tubing containing starch solution and glucose solution, suspended in a boiling tube of distilled water. After 30 minutes she tests the water outside. Benedict’s solution gives an orange precipitate; iodine solution stays orange-brown.
Explain both results, and explain why the tubing also gained mass.
▼
Size is the gatekeeper
Visking tubing is partially permeable: its pores let small molecules through and hold large ones back. Glucose molecules are small enough to diffuse out down their concentration gradient, so Benedict’s is positive outside. Starch molecules are far too large, so iodine stays negative outside.
Two movements, opposite directions
At the same time, the contents of the tubing are a solution, so they have a lower water potential than the distilled water outside. Water therefore moves in by osmosis and the tubing gains mass. Glucose out by diffusion, water in by osmosis — do not muddle them.
Biology Connection
This is exactly why food has to be digested. Starch cannot be absorbed; broken into glucose, it can. The model gut is the whole logic of digestion and absorption in one boiling tube, which is why examiners love it.
5
A locust has no lungs and no oxygen-carrying blood. Instead, fine air-filled tubes branch through its body and end microscopically close to each muscle cell. A biologist points out that a mouse of the same mass would die instantly with that system.
Why does the design work for the insect and not for the mouse?
▼
Bring the air to the cell, not the cell to the air
The tracheole system means the final diffusion distance is about 0.01 mm — astonishingly short. Diffusion over that distance is essentially instant, so no oxygen carrier is needed.
Why it does not scale up
To serve a mouse, the tubes would have to be longer and more branched, and diffusion along a long, narrow, gas-filled tube becomes too slow. A mammal instead uses mass flow — blood physically carrying oxygen most of the way — leaving diffusion to do only the last fraction of a millimetre from a capillary.
Biology Connection
Every transport system in biology exists for one reason: diffusion is superb over micrometres and useless over centimetres. Blood, xylem, phloem and tracheae are all ways of shortening the distance that diffusion is finally asked to cover.
Check Yourself: 3.1 Diffusion
20 multiple choice questions. Click an option to check your answer.
Your Score 0 / 20
Question 1
Which word must appear in the definition of diffusion for it to gain full credit?
A Fast
B Net
C Active
D Total
Diffusion is the net movement of particles down a concentration gradient. Without “net” the sentence describes a one-way stream of particles, which is not what happens.
Question 2
Where does the energy for diffusion come from?
A Respiration in the mitochondria
B The kinetic energy of the randomly moving particles
C Carrier proteins
D Sunlight
Diffusion is passive — the particles are already moving. Energy from respiration belongs to active transport only.
Question 3
Which factor, when increased, makes diffusion slower?
A Surface area
B Temperature
C Distance
D Concentration gradient
Three up, one down: surface area, temperature and gradient all speed diffusion up; only distance slows it.
Question 4
A cube of side 2 cm has a surface area to volume ratio of
A 6 : 1
B 3 : 1
C 2 : 1
D 8 : 1
Surface area = 6 × 2² = 24 cm²; volume = 2³ = 8 cm³; ratio = 3 : 1. The shortcut is ratio = 6 ÷ l.
Question 5
At equilibrium, particles in a solution
A stop moving
B move only downwards
C keep moving randomly, with no net movement
D move only towards the edges
Equilibrium means the concentrations are equal, not that motion has stopped. Equal numbers cross in each direction, so the net movement is zero.
Question 6
Which structure is adapted mainly to reduce the diffusion distance?
A A wall of the alveolus that is one cell thick
B The millions of alveoli in a lung
C The long extension of a root hair cell
D The folds of a villus
One cell thick means a very short distance. The other three all increase surface area, which is a different factor.
Question 7
Why does raising the temperature increase the rate of diffusion?
A It makes the concentration gradient steeper
B It gives the particles more kinetic energy so they move faster
C It makes the membrane more permeable
D It supplies energy from respiration
Heating adds no extra particles, so the gradient is unchanged. It changes only the speed at which the particles move.
Question 8
Oxygen keeps diffusing into a respiring muscle cell for hours. Why does the gradient not disappear?
A The cell pumps oxygen in
B Respiration keeps using the oxygen up inside the cell
C Oxygen is attracted to mitochondria
D The membrane traps oxygen
A gradient survives only if something keeps removing the substance at one end. Respiration does exactly that.
Question 9
Which pair of substances diffuses out of a respiring animal cell?
A Oxygen and glucose
B Carbon dioxide and urea
C Starch and protein
D Water and nitrate
Carbon dioxide and urea are made inside the cell, so their concentrations are higher inside and both move out. Oxygen and glucose move in.
Question 10
A student says that starch diffuses through Visking tubing. Why is this wrong?
A Starch is insoluble in water so cannot move
B Starch molecules are far too large to pass through the pores
C Visking tubing has no pores
D Starch is broken down by the tubing
Visking tubing is partially permeable: small molecules such as glucose pass, large molecules such as starch do not. That size difference is the whole point of the model gut.
Question 11
Which change would increase the rate of diffusion of oxygen into a single-celled organism?
A Thicker mucus on its surface
B Colder surrounding water
C Folds developing on its cell surface membrane
D Less oxygen in the surrounding water
Folds increase surface area. The other three all reduce the rate by increasing distance, lowering temperature or reducing the gradient.
Question 12
Diffusion is described as a passive process because
A it happens slowly
B the cell uses no energy from respiration
C it only occurs in dead cells
D it only moves gases
Passive means the cell pays nothing. Speed is irrelevant — over micrometres, diffusion is extremely fast.
Question 13
Which is the best explanation of why a large animal needs a transport system?
A Large animals respire faster
B Large animals have no concentration gradients
C The surface area to volume ratio is small and the distance to inner cells is large
D Diffusion does not occur in large animals
Both factors matter: less surface per unit of volume, and a much longer distance for diffusion to cover.
Question 14
Time taken for acid to reach the centre of an agar cube is found to be proportional to the length of the side. Which factor does this demonstrate?
A Temperature
B Concentration gradient
C Distance
D Surface area
Half the side length is the distance from surface to centre, so the result shows the effect of distance directly.
Question 15
Which of these is not a factor affecting the rate of diffusion in the 0610 syllabus?
A Surface area
B The pH of the solution
C Temperature
D Distance
The four named factors are surface area, temperature, concentration gradient and distance. Answers built on anything else earn nothing.
Question 16
The alveoli of the lungs are constantly ventilated by breathing. Which factor does this maintain?
A Distance
B The concentration gradient
C Surface area
D Temperature
Fresh air replaces the oxygen used and removes carbon dioxide, keeping the difference in concentration — the gradient — steep.
Question 17
Digested food is absorbed from the small intestine into the blood. Which statement is correct?
A Diffusion moves soluble food from the gut, where it is concentrated, into the blood, where it is less concentrated
B Diffusion moves food from the blood into the gut
C Starch diffuses straight into the blood
D No diffusion is involved in absorption
The gradient runs from gut to blood because blood flow constantly carries the absorbed food away.
Question 18
Which best explains why microvilli speed up absorption?
A They increase the temperature
B They increase the surface area of the membrane
C They increase the concentration gradient
D They shorten the small intestine
Folding a membrane multiplies its surface area without needing extra space, so many more molecules can cross per second.
Question 19
Oxygen diffuses into a cell faster when the temperature is higher because
A oxygen particles are attracted to warm membranes
B the particles have more kinetic energy and move faster
C the cell membrane becomes thinner when it is warm
D warmth reverses the direction of the gradient
Diffusion is driven by the random movement of particles. At a higher temperature the particles have more kinetic energy, so they move faster and diffuse faster. The gradient still runs the same way, from high concentration to low, and the membrane does not change thickness. Temperature is one of the four factors you will be asked about, with surface area, concentration gradient and distance.
Question 20
A student writes that particles “want to spread out evenly”. What is the correct version?
A Particles repel one another
B Particles are pulled apart by the solvent
C Particles move randomly, and more happen to leave a crowded region than enter it
D Particles spread only when the cell supplies energy
Nothing directs the movement. Diffusion is a statistical result of random motion — a point worth getting right now, because water potential depends on the same idea.
3.2 Osmosis ▼

Water Is the Solvent Everything Else Depends On

Before osmosis, why water matters at all. Water is the solvent of life: substances have to be dissolved before they can be moved, reacted or removed. Digestion: enzymes work in solution, so food molecules must be dissolved in water for enzymes to act on them, and the small, soluble products (glucose, amino acids) stay dissolved so they can be absorbed into the blood. Excretion: waste products such as urea, and excess ions, dissolve in water and are removed from the body in urine (and some in sweat). Transport: substances are carried dissolved in water: glucose, amino acids, ions, urea and carbon dioxide in blood plasma; mineral ions in xylem; sucrose in phloem. A substance that is not dissolved cannot be carried in these fluids. Nothing about a cell works dry.

And because water is such a good solvent, cells are surrounded by solutions of different concentrations — which is where the trouble starts.

Osmosis Is Just Diffusion, With Two Extra Conditions

Osmosis is not a new mechanism. It is diffusion — random movement producing a net drift — with two restrictions bolted on:

  • the substance that moves is water, and only water;
  • the barrier is a partially permeable membrane, which lets water through but holds larger solute molecules back.
osmosis: water moves from HIGH water potential → LOW water potential
Core definition: osmosis is the diffusion of water molecules from a dilute solution (or pure water) to a concentrated solution, through a partially permeable membrane. Supplement definition (learn this one): osmosis is the net movement of water molecules from a region of higher water potential to a region of lower water potential, through a partially permeable membrane. Water potential: a measure of how free the water molecules in a solution are to move out of it. Pure water has the highest water potential of all. Dissolve anything in it and the water potential falls. So a concentrated solution has a low water potential.
More Solute, Lower Water Potential

Say it out loud until it is automatic: more solute, less free water, lower water potential. Half the mistakes in this topic come from having the scale upside down. Once you have it the right way up, every direction question answers itself — water moves towards the lower water potential, which is the more concentrated side.

A partially permeable membrane Small water molecules pass both ways. Large sucrose molecules cannot pass at all. partially permeable membrane (never write "semi-permeable") DILUTE solution HIGH water potential CONCENTRATED solution LOW water potential many water molecules cross a few cross back — hence NET movement sucrose blocked
Blue circles are water molecules, orange ovals are sucrose. Water crosses in both directions — but more crosses from the dilute side, so the net movement is towards the concentrated side. Sucrose cannot cross at all, which is why the difference never evens out by itself.
Two Phrases That Quietly Cost Marks

1. “Semi-permeable”. This is the old term. Cambridge mark schemes want partially permeable. It is a free mark, and it is lost every year by students who understood the biology perfectly.

2. “Water moves to where there is more solute.” This gives the right prediction with the wrong mechanism, so it survives for years before failing you. Water molecules are not attracted by solute. They move at random; a concentrated solution simply has fewer free water molecules, which is what “lower water potential” means. Say down the water potential gradient and the mark is yours.

Plant Cells: Turgid, Flaccid, Plasmolysed

A plant cell is a bag of concentrated cell sap inside a partially permeable membrane, wrapped in a strong, inelastic cellulose cell wall. That wall changes everything.

The three states of a plant cell vacuole full TURGID in a dilute solution / water water entered by osmosis turgor pressure pushes out on the cell wall — firm vacuole smaller FLACCID some water lost by osmosis turgor pressure has fallen to zero membrane STILL touches the wall tissue is soft — the plant wilts shrunken gap fills with solution PLASMOLYSED in a concentrated solution much more water lost by osmosis membrane PULLS AWAY from wall wall keeps its shape throughout
Thick outer line = cell wall (unchanged in all three). Notice that the wall never crumples — in plasmolysis the membrane peels away from it, and the gap fills with the external solution.
StateSolution outsideWater movementWhat you would see
Turgidmore dilute than the cell sap (higher water potential)net movement invacuole full, contents pressed hard against the wall; tissue firm
Flaccidslightly more concentratednet movement outturgor pressure zero, membrane still against the wall; tissue soft
Plasmolysedmuch more concentrated (lower water potential)net movement outmembrane separated from the wall, contents shrunken into the middle
Supplement

Turgor pressure, and why plants stand up

As water enters a plant cell, the vacuole swells and pushes the cytoplasm outwards against the cell wall. The wall is strong and barely stretches, so it pushes back. That outward push of the contents on the wall is turgor pressure, and it rises until it exactly balances the tendency of water to enter — at which point net entry stops and the cell is fully turgid.

The syllabus wording is worth quoting exactly: plants are supported by the pressure of water inside the cells pressing outwards on the cell wall. Thousands of turgid cells pressed against each other make a stem rigid without any skeleton at all. Lose the water and the cells go flaccid, the pressure falls and the plant wilts. Water it and it stands up again within the hour — because nothing was broken, only depressurised.

Plasmolysis is also reversible in a living cell. Put a plasmolysed onion cell back in water and the protoplast expands and presses on the wall again. That recovery is the standard proof that the cell was alive all along.

Animal Cells: No Wall, No Mercy

An animal cell has a cell surface membrane and nothing else outside it. So when water floods in, there is nothing to push back — the cell simply swells until the membrane fails and it bursts. Red blood cells in distilled water do exactly this, and the mixture turns transparent red as their contents escape.

A red blood cell in three solutions Same osmosis as a plant cell — completely different outcome, because there is no cell wall distilled water higher water potential outside SWELLS AND BURSTS water enters by osmosis; no wall to resist the pressure 0.9 % salt (isotonic) same water potential as the cell NO NET CHANGE water still crosses both ways, but equally — used in drips 5 % salt solution lower water potential outside SHRINKS AND CRINKLES water leaves by osmosis NOT "plasmolysed" — no wall
This comparison is examined constantly. In a dilute solution the plant cell becomes turgid and the animal cell bursts; the only difference between them is the cell wall.
Four Words That Belong to Plant Cells Only

Turgid, turgor pressure, flaccid, plasmolysis all require a cell wall. Never use them for an animal cell. An animal cell in a dilute solution bursts; in a concentrated solution it shrinks and crinkles. Writing “the red blood cell was plasmolysed” is an instant lost mark even when the underlying reasoning is perfect.

The Potato Practical — and the Graph You Must Be Able to Read

This is the single most examined experiment in Topic 3, so learn the method as a story you could tell.

  1. Cut identical cylinders from one potato with a cork borer (different potatoes have different sap concentrations).
  2. Blot each one gently, weigh it, record the initial mass.
  3. Put one in each sucrose concentration for a fixed time.
  4. Remove, blot in exactly the same way, reweigh — the final mass.
  5. Calculate the percentage change in mass and plot it against concentration.
% change in mass = (final mass − initial mass) ÷ initial mass × 100
Always divide by the initial mass. Dividing by the final mass is the commonest error in the whole practical. Always give the sign. A positive value means water entered; a negative value means water left. The sign carries information, so it carries a mark. Why percentages? Because the cylinders never start with exactly the same mass, and a 0.4 g gain means something quite different in a 2 g cylinder and a 6 g one.
Percentage change in mass against sucrose concentration sucrose concentration / mol dm⁻³ change in mass / % +20 +10 0 −10 −20 0.0 0.2 0.4 0.6 0.8 1.0 ISOTONIC POINT ≈ 0.46 mol dm⁻³ read where the line crosses zero above the axis: mass GAINED solution more dilute than cell sap water entered — cells turgid below the axis: mass LOST solution more concentrated water left — cells flaccid
The point where the line crosses the concentration axis is the isotonic point: at this concentration the solution and the cell sap have the same water potential, so there is no net movement of water. It is the experiment’s way of measuring the concentration of the cell contents.
Reading the Isotonic Point — Three Marks, Three Traps

Trap 1: quoting the tested concentration that gave the smallest change instead of reading where the line crosses zero. Interpolate — the answer usually lies between two data points.

Trap 2: saying “osmosis has stopped”. It has not. Water molecules still cross the membrane both ways; the net movement is zero.

Trap 3: saying “the concentrations are equal” and stopping there. Say the water potentials are equal — that is the language of the supplement and it is what the mark scheme prints.

Worked Example 3 A potato cylinder has an initial mass of 4.50 g. After 40 minutes in 0.6 mol dm⁻³ sucrose its blotted mass is 4.32 g. Calculate the percentage change in mass and explain what happened to the cells. [4]
Step 1: Find the change, keeping the sign
change = 4.32 − 4.50 = −0.18 g. The mass fell, so the change is negative and stays negative all the way through.
Step 2: Divide by the INITIAL mass
(−0.18 ÷ 4.50) × 100 = −4.0 %. Dividing by 4.32 instead gives −4.2 % and loses the accuracy mark. Circle the initial mass in the question before you touch the calculator.
Step 3: Explain in water potential language
“The sucrose solution has a lower water potential than the cell sap, so there is a net movement of water molecules out of the cells by osmosis, through their partially permeable cell membranes. The cells lose water and become flaccid, so the cylinder loses mass.”
−4.0 % — water left the cells by osmosis because the solution had the lower water potential.
Worked Example 4 A student repeats the potato experiment with a potato that has been stored in a warm cupboard for three weeks. The isotonic point moves from 0.35 to 0.55 mol dm⁻³. What does this tell you about the stored potato, and why? [3]
Step 1: What does the isotonic point actually measure?
It measures the concentration of the cell sap: it is the external concentration that exactly balances it. Change the sap and the crossing point moves.
Step 2: Which way has it moved, and what does that mean?
A higher crossing point means a stronger external solution is now needed to balance the cells, so the cell sap must be more concentrated — and therefore has a lower water potential — than before.
Step 3: Why?
The potato has lost water by evaporation during three weeks in a warm dry cupboard. The same amount of solute is now dissolved in less water.
The stored potato has lost water, so its cell sap is more concentrated and has a lower water potential; a stronger sucrose solution is needed to balance it.

The Dialysis Tubing Practical

Method. Soak a 10 cm length of dialysis (Visking) tubing in water, knot one end, add 10 cm³ of 1.0 mol dm⁻³ sucrose solution, knot the other end, rinse, blot dry and weigh it. Place it in a beaker of distilled water. After 30 minutes remove it, blot it dry in the same way and reweigh it. Calculate the percentage change in mass.

Control. A second bag filled with distilled water and placed in distilled water. Its mass should not change, which shows that the change in the test bag is caused by the sucrose solution.

Why it works. The tubing is partially permeable: water molecules pass through, but sucrose molecules are too large. The sucrose solution has a lower water potential than the distilled water, so water enters the bag by osmosis and the bag gains mass.

Variation. Attach a capillary tube to the bag. The liquid rises up the tube as water enters; record the height every 5 minutes.

test: sucrose solution inside, distilled water outsidecontrol: distilled water inside and outside1.0 mol dm⁻³sucrosedistilledwaterliquid rises up thecapillary tube; readthe height on the rulerarrows: water enters by osmosispartially permeabledialysis tubingThe dialysis tubing practical, with its control
The test bag gains water by osmosis, so the liquid rises up the capillary tube. In the control there is no difference in water potential, so there is no net movement of water.
Worked Example 8 A dialysis bag of sucrose solution has an initial mass of 12.40 g. After 30 minutes in distilled water its mass is 13.64 g. Calculate the percentage change in mass. [2]
Step 1: Change in mass
13.64 − 12.40 = +1.24 g
Step 2: Divide by the starting mass
1.24 ÷ 12.40 × 100 = +10.0 %
+10.0 % (a gain) [2]. Always divide by the starting mass, and keep the sign.

Water Potential Decides Where Water Goes

Uptake by roots. The cell sap of a root hair cell contains dissolved sugars and ions, so it has a lower water potential than the soil water. Water therefore enters the root hair cell by osmosis through its partially permeable cell membrane. That cell now has a higher water potential than the cell next to it, so water passes from cell to cell across the root towards the xylem, always down the water potential gradient.

soil waterosmosisroot hair cellosmosiscortex cellosmosiscortex cellxylemwater potential: highest in the soil water, lowest in the xylemWater always moves down the water potential gradient
Water potential falls from the soil water to the xylem, so water keeps moving inwards.

Loss. If the soil water has a lower water potential than the cell sap (after salt water floods a field, or after far too much fertiliser) water leaves the root by osmosis and the plant wilts even though the soil is wet.

Animals. Red blood cells sit in plasma that has the same water potential as their cytoplasm, so there is no net movement of water. If the plasma became more dilute, water would enter and the cells could burst; if it became more concentrated, water would leave and the cells would shrink. This is why the water potential of the blood must be kept constant.

💧 Apply It: Osmosis Everywhere
Five everyday situations that are pure 3.2. Work out your answer first — then check the reasoning.
1
A cook in Kerala sprinkles salt over sliced cucumber and leaves it for twenty minutes. A pool of watery liquid collects in the bowl and the cucumber slices go limp and bendy.
Where did the liquid come from, and why did the cucumber go limp?
▼
The salt makes a very low water potential
Salt dissolving in the film of moisture on the cucumber creates a solution with a much lower water potential than the cell sap inside the cucumber cells.
Water leaves, turgor collapses
Water moves out of the cells by osmosis, down the water potential gradient, through their partially permeable membranes. The cells lose turgor pressure and become flaccid — and without that outward pressure on the cell walls, the tissue is soft. That is the limpness, and the pool in the bowl is the water that left.
Biology Connection
Exactly the same reasoning explains salting fish, sugaring jam and salt killing a slug. Every one of them works by giving the surroundings a water potential so low that cells — including bacterial cells — cannot hold on to their water.
2
A hospital drip contains 0.9 % sodium chloride solution, not distilled water. A student asks why the patient is not simply given pure water, which seems cleaner and more hydrating.
What would happen if pure water were dripped straight into a vein?
▼
Red blood cells have no cell wall
Pure water has the highest water potential possible, far above that of the cytoplasm of a red blood cell. Water would move into every red blood cell by osmosis, they would swell, and with only a membrane to hold them, they would burst.
Isotonic means no net movement
0.9 % saline has the same water potential as the cell contents. Water still crosses the membrane in both directions, but equally — so there is no net movement and the cells are unharmed.
Biology Connection
This is the clinical version of the isotonic point on your potato graph. The same idea sets the concentration of eye drops, contact lens solution and sports rehydration drinks.
3
A farmer in coastal Gujarat finds his wheat wilting in the middle of the day even though the soil is visibly wet. The field was flooded by sea water two seasons ago. A tough salt-tolerant grass is thriving in the same field.
How can a plant wilt in wet soil, and how does the grass survive?
▼
Wet is not the same as available
Salt dissolved in the soil water gives it a very low water potential — lower than the wheat’s root hair cell sap. So the gradient runs the wrong way and water moves out of the roots. The cells go flaccid, turgor is lost, and the plant wilts. This is called physiological drought.
The grass fights concentration with concentration
The salt-tolerant grass keeps a very high concentration of dissolved solutes in its cell sap, giving it an even lower water potential than the soil water. The gradient therefore still runs inwards and water enters by osmosis. It does not keep salt out; it out-concentrates the soil.
Biology Connection
Mangroves do the same thing to live with their roots in sea water. And it is why salinisation of irrigated farmland is such a serious problem — the soil is not dry, but as far as the crop is concerned it might as well be.
4
A student sets up a bag of dialysis tubing full of concentrated sucrose solution, attaches it to a capillary tube and stands it in distilled water. The liquid climbs the tube quickly at first, then more slowly, and after about an hour it stops rising at 78 mm.
Why does it rise, and why does it eventually stop?
▼
Why it rises
The sucrose solution has a lower water potential than the distilled water, so water enters the bag by osmosis through the partially permeable tubing. Sucrose cannot leave, so the extra volume has nowhere to go except up the narrow tube.
Two reasons it slows and stops
First, incoming water dilutes the sucrose, raising its water potential and making the gradient shallower. Second, the tall column of liquid exerts a growing downward pressure opposing further entry. When the two balance, net movement stops — though water molecules keep crossing in both directions.
Biology Connection
This is a plant cell built from glassware. The rising column is the equivalent of turgor pressure, and the levelling off is exactly what happens when a cell becomes fully turgid: the pressure rises until it cancels the tendency of water to enter.
5
A goldfish lives in a pond whose water is far more dilute than its body fluids. It never drinks, yet it produces large volumes of very dilute urine all day long. A sea fish of the same size drinks constantly and produces almost no urine.
Explain both patterns using water potential.
▼
Fresh water: the problem is too much water
Pond water has a higher water potential than the fish’s body fluids, so water moves in continually across the gills by osmosis. The fish does not need to drink, and the kidneys must dump the excess as copious dilute urine.
Sea water: the problem is losing water
Sea water has a lower water potential than the fish’s body fluids, so water moves out. The fish drinks sea water to replace it and conserves water by producing very little urine.
Biology Connection
Two identical-looking animals with exactly opposite water problems, and one principle explains both. That is what examiners mean by “applying knowledge to an unfamiliar context” — the biology never changes, only the direction of the gradient.
Check Yourself: 3.2 Osmosis
20 multiple choice questions. Click an option to check your answer.
Your Score 0 / 20
Question 1
Osmosis is the net movement of water molecules from a region of
A lower to higher water potential
B higher to lower water potential
C lower to higher solute concentration through any membrane
D higher to lower temperature
Water moves down the water potential gradient, which means from the dilute side towards the concentrated side, through a partially permeable membrane.
Question 2
Which term should you use for a cell membrane in an osmosis answer?
A Semi-permeable
B Fully permeable
C Partially permeable
D Impermeable
“Semi-permeable” is the older term and is not credited on 0610 mark schemes. Always write partially permeable.
Question 3
Which solution has the lowest water potential?
A Distilled water
B 0.2 mol dm⁻³ sucrose
C 0.6 mol dm⁻³ sucrose
D 1.0 mol dm⁻³ sucrose
More solute means fewer free water molecules and a lower water potential. Pure water sits at the very top of the scale.
Question 4
A plant cell is placed in distilled water. It becomes
A plasmolysed
B turgid
C flaccid
D burst
Water enters by osmosis, the vacuole swells and turgor pressure develops. The cell wall stops it bursting.
Question 5
A red blood cell placed in distilled water will
A become turgid
B become plasmolysed
C burst
D shrink and crinkle
An animal cell has no wall, so nothing resists the swelling and the membrane fails. Turgid and plasmolysed are plant-cell words only.
Question 6
In a plasmolysed plant cell,
A the cell wall has collapsed
B the cell membrane has pulled away from the cell wall
C the vacuole has burst
D the cell has died
The wall keeps its shape throughout; it is the membrane that separates from it. Plasmolysis is reversible in a living cell.
Question 7
A cylinder of potato has an initial mass of 4.20 g and a final mass of 4.62 g. The percentage change in mass is
A +9.1 %
B +10.0 %
C +0.42 %
D −10.0 %
(0.42 ÷ 4.20) × 100 = +10.0 %. Dividing by the final mass gives +9.1 % — the classic error.
Question 8
On a graph of percentage change in mass against concentration, the point where the line crosses zero shows
A the concentration at which the cells are fully plasmolysed
B the concentration at which osmosis stops completely
C the concentration with the same water potential as the cell contents
D the highest concentration the cells survive
Zero change means no net movement, so the water potentials are equal. Water molecules still cross both ways.
Question 9
Why must potato cylinders be blotted before weighing?
A To stop osmosis continuing
B To remove surface solution that would be weighed as part of the cylinder
C To dry the tissue out
D To remove damaged cells
A film of liquid on the outside adds mass that has nothing to do with water entering or leaving the cells. Blot gently and identically every time.
Question 10
Which is the correct order from most water gained to most water lost?
A turgid, flaccid, plasmolysed
B plasmolysed, flaccid, turgid
C flaccid, turgid, plasmolysed
D turgid, plasmolysed, flaccid
Turgid = full; flaccid = turgor pressure lost; plasmolysed = so much water lost that the membrane has separated from the wall.
Question 11
A plant wilts because
A the cell walls collapse
B the cells lose turgor, so the pressure pushing outwards on the cell walls is lost
C the chloroplasts stop working
D the vacuoles fill with air
Support in a non-woody plant comes from the pressure of water inside the cells pressing outwards on the cell walls. The walls themselves are unchanged.
Question 12
Dialysis tubing containing sucrose solution is placed in distilled water. After an hour the tubing has
A lost mass, as sucrose escaped
B gained mass, as water entered by osmosis
C not changed
D gained mass, as sucrose entered
Water passes through the pores; sucrose molecules are too large. A Benedict’s test on the beaker water stays negative, which proves it.
Question 13
Which is not an example of water acting as a solvent?
A Urea dissolved in urine
B Glucose dissolved in blood plasma
C Cellulose dissolved in cell walls
D Digestive reactions in solution
Cellulose is famously insoluble in water — which is exactly what makes it a good structural material for cell walls.
Question 14
Root hair cells absorb water because
A the soil solution has a higher water potential than the cell sap
B the soil solution has a lower water potential than the cell sap
C water is actively transported into the root
D carrier proteins pump water inwards
Soil water is dilute so its water potential is high; the cell sap is concentrated so its water potential is low. Water is never moved by active transport.
Question 15
A fully turgid plant cell stops gaining water because
A the membrane becomes impermeable
B water molecules stop moving
C turgor pressure balances the tendency of water to enter
D the vacuole is completely full of solute
The wall pushes back until entry and exit are equal — net movement zero, individual molecules still crossing.
Question 16
Red onion epidermis is used for plasmolysis experiments because
A its cells have no wall
B it is one cell thick and the coloured sap makes the shrunken contents visible
C its cells are dead
D it has no vacuole
A single layer can be viewed directly, and the pigment in the vacuole outlines the protoplast as it pulls away from the wall.
Question 17
Which change would increase the rate at which water enters a plant cell by osmosis?
A Raising the solute concentration outside
B Lowering the solute concentration outside
C Increasing the turgor pressure inside
D Removing the cell wall
A more dilute external solution has a higher water potential, so the gradient into the cell is steeper.
Question 18
Salt sprinkled on a slug kills it because
A salt ions poison the cells immediately
B the salt raises the water potential outside so water rushes in
C the salt lowers the water potential outside so water leaves the cells
D salt dissolves the cell walls
Adding solute always lowers water potential. Slugs are animals, so they have no cell walls in the first place.
Question 19
Two dialysis bags contain sucrose solutions and sit in identical beakers of distilled water. Bag P gains 1.8 g and bag Q gains 0.6 g. What can be concluded?
A Bag P contained the more concentrated solution
B Bag Q contained the more concentrated solution
C Bag P was made of more permeable material
D Sucrose leaked out of bag Q
A more concentrated solution has a lower water potential, so the gradient is steeper and water enters faster.
Question 20
A student writes: “Water moves by osmosis because the solute attracts it.” What is the correct explanation?
A Solutes physically pull water molecules towards them
B Water moves at random, and a concentrated solution has fewer free water molecules and a lower water potential
C Water is pushed by pressure from the dilute side
D Osmosis is powered by respiration
The prediction happens to be right, but the mechanism is wrong — and questions asking why will expose it. Water responds to its own gradient, not to the solute.
3.3 Active Transport ▼
▶  Watch: Active Transport
Opens on YouTube in a new tab. Watch one, then come back and do the Check Yourself questions — watching without testing yourself feels like learning but is not.

The Big Idea: Sometimes a Cell Has to Push Uphill

Diffusion and osmosis are free, but they will only ever take you downhill. A root hair cell in dilute soil water already contains far more nitrate than the soil around it. Diffusion would carry nitrate out. If the plant relied on diffusion it would slowly leak away the very ions it needs.

So the cell cheats. It spends energy to move ions against their concentration gradient — from where they are scarce to where they are already plentiful. That is active transport, and it is the only one of the three processes that costs the cell anything.

active transport = movement AGAINST the gradient, paid for by respiration
Definition: active transport is the movement of particles through a cell membrane from a region of lower concentration to a region of higher concentration (against a concentration gradient), using energy released by respiration. Both halves are needed. An answer that gives only the direction, or only the energy, is a half answer — and mark schemes usually split the marks exactly that way. Supplement: protein carriers in the cell membrane move the molecules or ions across it. Each carrier is specific, so the cell can take up one substance and ignore another.

How a Protein Carrier Works

A carrier protein spans the whole thickness of the membrane. An ion binds to it on the outside; the carrier uses energy from respiration to change shape; the ion is released on the inside. The carrier then returns to its original shape, ready for the next one. Nothing is broken down and nothing is rebuilt — the nitrate that binds is the nitrate that arrives.

A root hair cell taking up mineral ions SOIL WATER very dilute in nitrate ions cell wall protein carrier cell membrane (partially permeable) ACTIVE TRANSPORT OSMOSIS (water, passive) ROOT HAIR CELL CYTOPLASM already about 100× more concentrated in nitrate mitochondria — aerobic respiration releases the ENERGY root hair cells contain unusually many of them
Two movements across the same membrane at the same time, in the same direction, by completely different mechanisms: ions pushed uphill through protein carriers using energy from respiration, and water drifting downhill by osmosis for free.
The Question That Sorts Everyone Out

“Why do root hair cells contain many mitochondria?” The wrong answer — and it is very common — is “for osmosis”. Osmosis is passive and costs the cell nothing at all, so mitochondria have nothing to do with water uptake. The right answer is: mitochondria are the site of aerobic respiration, which releases the energy needed for the active transport of mineral ions against a concentration gradient. Three links, often three marks.

How to Prove a Movement Is Active

Because active transport is the only one of the three that depends on respiration, you can switch it off. Take away the oxygen, add a respiratory inhibitor such as cyanide, or cool the tissue to a few degrees above freezing — and:

TreatmentDiffusion / osmosisActive transport
Remove oxygen (nitrogen atmosphere, waterlogged soil)continues almost unchangedfalls dramatically
Respiratory inhibitor (e.g. cyanide)continuesstops
Cool to 5 °Cslows a littlealmost stops
Block the carrier proteinswater still crosses freelystops

So a data table showing that a movement stops without oxygen and runs from low to high concentration is a two-line proof of active transport. That is why experiments of exactly this shape turn up in Paper 4 every year.

Supplement

Why active transport matters

Ion uptake by root hairs. Soil water is extremely dilute in nitrate, phosphate, potassium and magnesium, yet plants need all of them — nitrogen for amino acids and proteins, magnesium for chlorophyll. Without active transport a plant simply could not obtain them, however wet the soil.

Absorption in the small intestine. Glucose and amino acids are absorbed until virtually none is left in the gut — long after the gradient has reversed. Only active transport can finish the job, which is why gut lining cells are packed with mitochondria and covered in microvilli.

Reabsorption in the kidney. Glucose is reabsorbed from the kidney tubule back into the blood until the urine contains none at all — again, working against the gradient.

Carrier saturation. Because there is a fixed number of carriers, the rate of active transport reaches a plateau at high external concentrations: every carrier is already working flat out. Simple diffusion, by contrast, keeps rising in a straight line. That difference in graph shape is itself evidence for which process is operating.

Worked Example 5 Barley roots take up potassium ions from a dilute solution. Uptake is 4 units at 0 % oxygen, 22 units at 5 %, 38 units at 10 % and 50 units at 21 %. Explain these results, and suggest why uptake is not zero at 0 % oxygen. [5]
Step 1: Establish the direction first
The cells already contain far more potassium than the solution, so the ions are moving against the concentration gradient. That immediately rules out diffusion and osmosis and tells you energy must be involved.
Step 2: Build the chain, one mark per link
More oxygen → more aerobic respiration → more energy released → more energy available to the protein carriers → more ions moved per hour. Quote data as you go: uptake rises from 4 to 50 units, a more than twelvefold increase.
Step 3: The “suggest” part — reason, do not recall
Two creditable ideas: anaerobic respiration still releases a small amount of energy, so a little active transport continues; and a small amount may enter by diffusion, which needs no energy at all. “Experimental error” throws away a mark that reasoning would have earned.
Uptake is by active transport driven by aerobic respiration, so it rises with oxygen; the residual uptake without oxygen comes from anaerobic respiration and from a little diffusion.
⚡ Apply It: Paying for Transport
Four situations where the cell is spending energy. In each case, ask first: which way is the gradient running?
1
Heavy monsoon rain leaves a field near Pune waterlogged for a week. The crop has plenty of water but its leaves turn pale yellow and growth stops. A neighbouring field with the same soil, well drained, is dark green.
Why does too much water cause a shortage of minerals?
▼
Water fills the air spaces
Waterlogged soil has almost no air in it, so root cells cannot obtain oxygen and aerobic respiration falls sharply. Roots respire just as leaves do.
No respiration, no carriers, no ions
Less energy is released, so the protein carriers cannot run and active transport of mineral ions almost stops. The plant is short of nitrate — needed for amino acids and proteins — and magnesium, needed for chlorophyll. Hence pale leaves and stunted growth.
Biology Connection
Notice the shape of the argument: oxygen → respiration → energy → active transport → ion uptake → growth. Almost every applied active-transport question is this same chain with a different story wrapped round it.
2
Glucose is absorbed from the small intestine until essentially none remains in the gut contents — even though the blood already contains plenty of glucose. In the kidney, glucose is reabsorbed from the tubule until the urine contains none at all.
Why can diffusion not account for either observation?
▼
Diffusion always quits early
Diffusion stops producing net movement as soon as the concentrations are equal. If absorption were purely diffusion, glucose would always be left behind in the gut and in the urine — and it is not.
Finishing the job costs energy
Removing the last of the glucose means moving it against its concentration gradient, which requires energy released by respiration and specific carrier proteins. That is why both the gut lining and the kidney tubule cells are crammed with mitochondria.
Biology Connection
The rule to carry into every question: the identity of the molecule never tells you the process. Glucose moves by diffusion in some places and by active transport in others. Only the direction of the gradient decides.
3
A researcher measures the uptake of a substance as its external concentration is raised. With oxygen present, uptake climbs steeply and then flattens out completely above a certain concentration. Without oxygen, uptake is much lower but keeps climbing steadily with no flattening at all.
What do the two graph shapes tell you?
▼
A plateau means a fixed number of something
With oxygen, uptake is largely by active transport through protein carriers. There is a fixed number of carriers, so once they are all working flat out, adding more of the substance outside cannot speed anything up. The line levels off.
A straight climb means simple diffusion
Without oxygen there is little energy for active transport, so what remains is mostly diffusion, whose rate depends only on the steepness of the concentration gradient. Raise the outside concentration and the rate simply keeps rising.
Biology Connection
You can identify a transport process from the shape of a graph without being told anything else. Plateau plus oxygen-dependence equals active transport; straight line with no oxygen-dependence equals diffusion.
4
A single-celled organism living in a freshwater pond has a structure that fills with water and then squeezes it out of the cell, over and over, twenty times a minute. Stop the organism respiring and the structure stops working — and the cell swells and bursts.
Why does removing water from this cell require energy, when water normally moves for free?
▼
Water is being moved the wrong way
The pond water has a higher water potential than the cytoplasm, so osmosis drives water in continuously. Getting it back out means moving water against the water potential gradient — and nothing moves uphill for free.
Stop respiring and osmosis wins
Without energy from respiration the pumping stops, water keeps entering by osmosis, and with no cell wall to resist the pressure the cell bursts. The cell is not fighting a lack of water; it is fighting a constant excess.
Biology Connection
The general principle is the one to take away: any movement up a gradient must be paid for by respiration. In an exam answer, keep the phrase “active transport” for ions and molecules, and describe this as removing water using energy from respiration.
Check Yourself: 3.3 Active Transport
20 multiple choice questions. Click an option to check your answer.
Your Score 0 / 20
Question 1
Active transport moves particles
A down a concentration gradient using no energy
B against a concentration gradient using energy released by respiration
C only when the cell is short of water
D through a partially permeable membrane by random movement
Both halves are needed for full credit: against the gradient and energy from respiration.
Question 2
The energy for active transport comes from
A the kinetic energy of the particles
B sunlight
C respiration, mostly in the mitochondria
D the concentration gradient
A gradient is not a fuel store — active transport works against it. Kinetic energy powers diffusion instead.
Question 3
Nitrate ions enter a root hair cell that already contains far more nitrate than the soil. The process must be
A diffusion
B osmosis
C active transport
D evaporation
The direction of the gradient decides. Uphill movement can only be active transport.
Question 4
Root hair cells contain many mitochondria because
A they store glucose
B they need energy from respiration for active transport of mineral ions
C they need energy for osmosis
D they make the cell wall
Osmosis is passive and costs the cell nothing, so “for osmosis” is a guaranteed lost mark.
Question 5
What do protein carriers do?
A Make holes that let anything through
B Break particles down so they fit through
C Bind specific ions and use energy to move them across the membrane
D Release energy from glucose
Carriers are specific, which is why a cell can take up nitrate and ignore other ions. Energy is released in the mitochondria, not by the carrier itself.
Question 6
A root is treated with a chemical that stops respiration. What happens?
A Water uptake and ion uptake both stop
B Water uptake continues but ion uptake stops
C Ion uptake continues but water uptake stops
D Neither is affected
Osmosis needs no energy from the cell, so it carries on; active transport of ions depends on respiration and stops.
Question 7
Which observation is the strongest evidence for active transport?
A The substance moves faster when warmed
B The substance accumulates against its gradient and uptake stops without oxygen
C The substance is a small ion
D The substance crosses the cell membrane
Warming speeds up every process, so it distinguishes nothing. The two decisive features are the uphill direction and the oxygen dependence.
Question 8
Waterlogged soil reduces mineral ion uptake because
A waterlogged soil contains no ions
B roots lack oxygen so respiration and therefore active transport are reduced
C water dilutes the ions inside the plant
D osmosis blocks the carriers
The chain is oxygen → respiration → energy → active transport → ion uptake.
Question 9
Uptake of a substance rises with external concentration and then plateaus. The best explanation is
A the membrane has dissolved
B all the carrier proteins are saturated
C the gradient has reversed
D the particles have stopped moving
A plateau means something with a fixed number has become limiting. Simple diffusion would keep rising in a straight line.
Question 10
Glucose is reabsorbed from a kidney tubule until none is left in the urine. This shows that
A diffusion alone is responsible
B osmosis is responsible
C active transport must be involved
D the tubule is impermeable to glucose
Diffusion stops as soon as concentrations equalise, so it could never remove the last of the glucose.
Question 11
Which structure would you expect in large numbers in a cell specialised for active transport?
A Chloroplasts
B Mitochondria
C Vacuoles
D Cell walls
Aerobic respiration in the mitochondria releases the energy that active transport depends on.
Question 12
Cooling root tissue to 5 °C almost stops ion uptake but barely affects water uptake. Why?
A Ions freeze at 5 °C
B Cold reverses the gradient
C Cold slows respiration greatly, and only active transport needs its energy
D Cold makes the membrane impermeable to ions
This is the temperature version of the respiratory-poison experiment and is a standard way of showing a process is active.
Question 13
Which row correctly compares the three processes?
A All three need energy from respiration
B Only osmosis needs a partially permeable membrane
C Diffusion and osmosis are passive and go down a gradient; active transport goes up a gradient using energy from respiration
D Diffusion moves water only, osmosis moves solutes only
Direction plus energy is the cleanest summary of the whole topic.
Question 14
Active transport is important to plants mainly because it allows them to
A absorb water from dry soil
B absorb mineral ions from very dilute soil water
C lose water from leaves
D take in carbon dioxide against a gradient
Soil water is extremely dilute in ions, so uptake has to run uphill. Water uptake is osmosis and needs no energy.
Question 15
In active transport, the ion that binds to a carrier protein
A is broken down and rebuilt inside the cell
B is released unchanged on the other side of the membrane
C is dissolved into the membrane
D is carried in by a water molecule
The carrier changes shape using energy; the ion itself is unchanged. Nothing is dismantled.
Question 16
Which of these is not affected by a lack of oxygen?
A Active transport of nitrate into a root hair
B Reabsorption of glucose in a kidney tubule
C Osmosis into a potato cylinder
D Uptake of potassium ions by barley roots
Osmosis is passive and runs on the kinetic energy of water molecules, so it continues regardless.
Question 17
Cells lining the small intestine have microvilli and many mitochondria. These provide, respectively,
A a large surface area and energy for active transport
B energy and a large surface area
C a partially permeable membrane and water
D carrier proteins and glucose
Two features, two different reasons — giving the same reason for both loses a mark.
Question 18
A substance moves into a cell from low to high concentration and movement stops when a respiratory inhibitor is added. The substance is potassium ions. Which process is it?
A Diffusion
B Osmosis
C Active transport
D Evaporation
Osmosis can be eliminated immediately, because osmosis moves water and nothing else, whatever is dissolved in it.
Question 19
Which statement about diffusion and active transport is correct?
A Both move substances down a gradient
B Diffusion goes down a gradient, active transport goes up
C Diffusion goes up a gradient, active transport goes down
D Both move substances in whichever direction the cell needs
Diffusion never obeys the cell’s requirements; only active transport does, which is what the energy pays for.
Question 20
A plant is given a chemical that blocks the carrier proteins in its root cell membranes. The most likely result is
A water uptake stops but ion uptake continues
B ion uptake falls sharply while water uptake by osmosis continues
C both stop immediately
D photosynthesis stops immediately
Water crosses the membrane without carriers, so blocking carriers knocks out ion uptake alone.
3.4 Exam Technique & the Exact Words Cambridge Wants ▼

Why This Topic Loses More Marks Than It Should

Topic 3 is not hard. Almost everyone who loses marks here understands the biology perfectly well. What they lose marks for is wording — and because the same three or four phrases appear in every question, the same marks are lost over and over again. This section is a repair kit.

What students writeWhy it failsWrite this instead
“particles move from high to low concentration”describes a one-way stream; particles actually move in all directions“the net movement of particles from a region of higher to lower concentration”
“semi-permeable membrane”the older term; not on the mark scheme“partially permeable membrane”
“water moves to where there is more solute”right prediction, wrong mechanism — solutes do not attract water“water moves down the water potential gradient, from higher to lower water potential”
“osmosis stops” / “the particles stop moving”movement never stops; only the balance changes“there is no net movement”
“the red blood cell was plasmolysed”plasmolysis needs a cell wall“the red blood cell burst” or “shrank and crinkled”
“the plant cell burst”the cell wall prevents this“the plant cell became turgid”
“water is actively transported into the root”there is no such thing; water is never actively transported“water enters by osmosis”
“the mitochondria provide energy for osmosis”osmosis is passive and costs the cell nothing“energy from respiration is needed for active transport of ions”
“it is a fair test”names no variable“the concentration gradient was kept the same so only the size varied”
“the salt sucks the water out”not a mechanism“the salt solution has a lower water potential, so water leaves by osmosis”
Four Words, Four Owners

Turgid, turgor pressure, flaccid, plasmolysed — plant cells only, because all four depend on the cell wall.
Burst, shrink, crinkle — animal cells only, because they have no wall.
Getting these the wrong way round is the fastest way to lose a mark you had already earned.

The Three Sentence Templates

Almost every explanation in this topic is one of three sentences with the nouns changed. Learn them as templates and you will never be stuck for the first line of an answer.

Template 1 — osmosis
“The [solution] has a lower / higher water potential than the [cell contents], so there is a net movement of water molecules [out of / into] the cells by osmosis, through the partially permeable cell membrane. The cells therefore become [turgid / flaccid / plasmolysed].”
Template 2 — active transport
“The [ions] are already more concentrated inside the cell, so they are moved against the concentration gradient by active transport. The energy for this is released by respiration in the mitochondria, and the ions are carried across by protein carriers in the membrane.”
Template 3 — a maintained gradient
“[Respiration / photosynthesis / the blood flow] continually [uses up / removes] the [oxygen / carbon dioxide / glucose], so its concentration inside stays [low / high] and the concentration gradient is maintained.”

Command Words — What Each One Is Actually Asking

CommandWhat to doTypical Topic 3 example
State / Nameone short answer, no reason needed“Name the process by which water enters a root hair cell.”
Describesay what happens, with figures if there is data“Describe how uptake changes as oxygen concentration increases.”
Explainsay why — every “because” is a potential mark“Explain why the plant cell does not burst.”
Suggestthe answer is not in your notes; reason from principles“Suggest why uptake is not zero without oxygen.”
Calculateshow working, give the unit and the sign“Calculate the percentage change in mass.”
Predictstate the outcome and justify it from the pattern“Predict the time taken for a 25 mm cube.”
Compareuse comparative words, and use a matched pair of figures“Compare uptake with and without oxygen.”
Marks Follow the Number in Brackets

A three-mark “explain” wants three separate ideas, not one idea said three ways. In this topic the three are almost always: the direction of the gradient, the process and how it crosses the membrane, and the consequence for the cell or tissue. Before you write, count the marks and plan that many distinct points.

Data and Graph Technique

SkillHow to earn the markHow it is thrown away
Reading an isotonic pointread where the line crosses zero, interpolating between pointsquoting the tested concentration nearest to zero instead
Describing a trendstate the direction and quote figures with units from both ends“it goes up” with no data
Comparing two data setsuse a matched pair from the same row or columnpicking two numbers at random from different conditions
Explaining a plateauname what has become limiting — usually the number of carrier proteins“the cell is full”
Drawing a conclusionstay inside the range testedextrapolating: “so it keeps rising forever”
Evaluatingname a specific weakness and its effect on the result“there could have been errors”
The Percentage Change Checklist

Every single time: 1. change = final − initial (keep the sign). 2. divide by the initial mass, never the final. 3. multiply by 100. 4. write the sign in the answer. 5. sanity check — gained mass means water entered, which means the solution was more dilute than the cell sap.

The Decision Tree for “Which Process?”

Water across a membrane? → OSMOSIS. Otherwise, which way does the gradient run?
Step 1. Is water crossing a partially permeable membrane? If yes, it is osmosis, whatever is dissolved in it. Osmosis moves water and nothing else. (Water vapour moving through the air spaces of a leaf and out of the stomata is diffusion, because it crosses no membrane.) Step 2. If it is not water, is it moving from high to low concentration? That is diffusion, and it is free. Step 3. Is it moving from low to high concentration? That is active transport, and it needs energy from respiration and protein carriers. Step 4. Check your answer against the evidence: if the movement stops without oxygen, it was active transport. If it continues, it was passive.
Worked Example 6 “Explain, in terms of water potential, what happens to plant cells placed in a concentrated sucrose solution.” [3] — Two answers are shown below. Decide which marks each would score.
Answer A — scores 1 of 3
“The sucrose has more solute so it sucks the water out of the cells through the semi-permeable membrane and the cells go floppy and die.”

The idea that water leaves is credited once. But “sucks” is not a mechanism and the question demanded water potential; “semi-permeable” is the wrong term; “floppy” is not flaccid or plasmolysed; and the cells are not dead — plasmolysis is reversible.
Answer B — scores 3 of 3
“The sucrose solution has a lower water potential than the cell sap. There is therefore a net movement of water molecules out of the cells by osmosis, through the partially permeable cell membranes. The cells lose water and become flaccid, and in a strongly concentrated solution the membrane pulls away from the cell wall, so the cells become plasmolysed.”
What changed
Not the understanding — both students knew water left the cells. What changed was five words: lower water potential, net, partially permeable, flaccid, plasmolysed. That is the whole difference between a grade C answer and a grade A answer in this topic.
Precision of vocabulary is the skill being assessed. Learn the templates and use them word for word.
📝 Apply It: Marking Someone Else’s Answer
The fastest way to stop making an error is to spot it in someone else’s work. Read each answer, decide what is wrong, then open the card.
1
Question: “Define diffusion. [2]”
Student answer: “Diffusion is when particles move from a high concentration to a low concentration until they are evenly spread and then they stop.”
How many marks, and what exactly went wrong?
▼
Zero or one mark — two separate errors
The word net is missing, so the sentence describes a one-way procession of particles. And “then they stop” is actively wrong: at equilibrium particles keep moving randomly, and equal numbers cross in each direction.
The repaired answer
“Diffusion is the net movement of particles from a region of their higher concentration to a region of their lower concentration, down a concentration gradient, as a result of their random movement.”
Exam Connection
The random-movement phrase is often worth the second mark on its own, and it also explains why diffusion needs no energy from the cell — a follow-up question that appears constantly.
2
Question: “Explain why root hair cells contain many mitochondria. [2]”
Student answer: “Because they need lots of energy to take in water by osmosis from the soil.”
Why does this score nothing at all?
▼
The one process that needs no energy
Osmosis is passive. It runs on the kinetic energy of the water molecules and costs the cell nothing, so linking mitochondria to osmosis is a biological error rather than an incomplete answer — which is why it scores zero rather than one.
The repaired answer
“Mitochondria are the site of aerobic respiration, which releases energy. Root hair cells need a lot of energy for the active transport of mineral ions from the dilute soil water into the cell, against a concentration gradient.”
Exam Connection
Whenever you write “energy” in this topic, check which process you have attached it to. Only active transport is allowed to have it.
3
Question: “A graph of percentage change in mass crosses zero at 0.42 mol dm⁻³. Explain what this shows. [2]”
Student answer: “At 0.42 the potato and the solution are the same, so osmosis has stopped.”
One mark at most — why?
▼
“The same” is too vague, and “stopped” is wrong
The same what? The mark scheme wants water potential. And osmosis has not stopped — water molecules continue to cross the membrane in both directions; what is zero is the net movement.
The repaired answer
“At 0.42 mol dm⁻³ the sucrose solution has the same water potential as the potato cell sap, so there is no net movement of water into or out of the cells and the mass is unchanged.”
Exam Connection
“No net movement” is the single most valuable three-word phrase in Topic 3. It answers the isotonic point, the fully turgid cell, the isotonic drip and the equilibrium question — four different questions, one phrase.
Check Yourself: 3.4 Exam Technique & Vocabulary
20 multiple choice questions. Click an option to check your answer.
Your Score 0 / 20
Question 1
Which word is missing from “diffusion is the movement of particles down a concentration gradient”?
A Fast
B Net
C Complete
D Active
Without net the sentence describes a one-way stream of particles, which is not what happens.
Question 2
Which term does the 0610 mark scheme require for a membrane that lets water through but not sucrose?
A Semi-permeable
B Selectively porous
C Partially permeable
D Impermeable
“Semi-permeable” is the older wording and is not credited. This is a free mark lost every year.
Question 3
Which phrase should replace “osmosis has stopped”?
A Osmosis has finished
B There is no net movement of water
C The water potential is zero
D The membrane has closed
Water molecules go on crossing in both directions; only the net movement is zero.
Question 4
Which word may not be used to describe an animal cell?
A Burst
B Shrunken
C Plasmolysed
D Crinkled
Plasmolysis is the membrane pulling away from the cell wall, and animal cells have no wall.
Question 5
A three-mark “explain” question requires
A one idea written in three sentences
B three separate creditable ideas
C three examples of the same process
D a diagram
Count the marks and plan that many distinct points. In this topic they are usually gradient, process, consequence.
Question 6
A question says “suggest”. This means
A the answer is a definition you have learnt
B you must reason from principles because the exact answer is not in your notes
C you may guess
D you should describe the method
“Suggest” signals an unfamiliar context. Apply a rule you know rather than trying to recall a fact.
Question 7
When calculating percentage change in mass you must divide by the
A final mass
B initial mass
C mean of the two masses
D volume of solution
Dividing by the final mass is the single most common error in the potato practical.
Question 8
Which is the strongest way to describe a trend from a data table?
A “It goes up.”
B “There is a relationship.”
C “Uptake rises from 4 to 50 arbitrary units as oxygen rises from 0 to 21 %.”
D “The results vary.”
Description marks nearly always require figures with units quoted from the data.
Question 9
A student concludes from data covering 10–40 °C that “diffusion keeps getting faster however hot it gets”. The error is
A a calculation mistake
B extrapolating beyond the range tested
C using the wrong units
D confusing rate and time
Conclusions must stay inside the range investigated. This is an easy evaluation mark to earn or throw away.
Question 10
Which is a valid evaluation point rather than an empty one?
A “There could have been errors.”
B “The experiment was not fair.”
C “The edge of the coloured circle was fuzzy, so judging the diameter was subjective.”
D “More care was needed.”
Evaluation marks need a specific weakness and its effect on the measurement.
Question 11
“It is a fair test” scores nothing. What should you write instead?
A “All variables were controlled.”
B “The concentration of the solution was kept the same, so only the size of the tissue varied.”
C “The results were reliable.”
D “The method was accurate.”
Name the variable and say what it would otherwise have changed — usually one of the four factors affecting diffusion.
Question 12
Which sequence is the correct decision tree for identifying a transport process?
A Is it an ion? Is it small? Is it warm?
B Is it water? If not, which way does the gradient run? Does it stop without oxygen?
C Is the cell alive? Is it a plant? Is it in solution?
D Is it fast? Is it passive? Is it useful?
Water is always osmosis; direction separates diffusion from active transport; oxygen dependence confirms it.
Question 13
Repeating each concentration three times and taking a mean improves
A accuracy
B reliability
C the resolution of the balance
D the concentration gradient
Repeats and means improve reliability; better instruments and technique improve accuracy. Mark schemes distinguish the two.
Question 14
Which phrase correctly completes: “The salt solution has a lower water potential, so…”?
A …it sucks water out of the cells.
B …there is a net movement of water out of the cells by osmosis.
C …the water is attracted to the salt.
D …the cells actively transport water out.
Avoid “sucks” and “attracts”: neither is a mechanism, and water is never actively transported.
Question 15
A question asks you to “compare” two sets of results. The best technique is to
A describe each set separately in turn
B quote a matched pair of figures from the same concentration and use comparative language
C state which set is better
D calculate the mean of all the values
A comparison needs the two values that can actually be compared, taken from the same row or column.
Question 16
Which is the correct order of the three ideas in a full osmosis explanation?
A Consequence, process, gradient
B Gradient, process and membrane, consequence for the cell
C Process, temperature, gradient
D Membrane, energy, gradient
Water potential comparison first, then net movement by osmosis through the partially permeable membrane, then turgid, flaccid or plasmolysed.
Question 17
“Predict what happens to a 25 mm cube.” A full-mark answer must include
A only the numerical prediction
B the prediction and a justification from the pattern in the data
C a diagram of the cube
D a repeat of the method
Predictions are always marked as outcome plus justification, and the justification must come from the data.
Question 18
Which statement about the four factors affecting the rate of diffusion is correct?
A All four increase the rate when increased
B Three increase the rate; increasing distance decreases it
C Only temperature and surface area matter
D Concentration gradient is not one of them
Three up, one down. Distance is the only factor that slows diffusion when increased.
Question 19
Why is “water moves to where there is more solute” dangerous even though it predicts correctly?
A It is too long
B It fails as soon as a question asks why, because it names no gradient and no mechanism
C It only works for sucrose
D It is only true for plant cells
It survives for years because the prediction is right, and then collapses on any “explain” question.
Question 20
The most valuable three-word phrase in Topic 3 is
A “energy from respiration”
B “no net movement”
C “against the gradient”
D “partially permeable membrane”
It answers the isotonic point, the fully turgid cell, the isotonic drip and the equilibrium question — four questions, one phrase. The others are valuable too, but this one is reused most.