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IGCSE Mathematics Paper 2 (Extended) — non-calculator

Unit Assessment Mock 6 -- Sets, Percentages, Time, Money -- 40 marks in 45 minutes
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Instructions

Question 1 — Sets
Total: 10 marks
Information for the whole question
50 people in a café were asked which of three drinks they like: tea ( T ), coffee ( C ) and juice ( J ).

    31 like tea  ·  26 like coffee  ·  23 like juice
    14 like tea and coffee  ·  13 like tea and juice  ·  11 like coffee and juice
    6 like all three

The Venn diagram below is provided for your working. Nothing has been filled in. Note that "14 like tea and coffee" counts everybody in T ∩ C , including the 6 who like all three.
ξ T C J
(a)(i) [3]
Find the number of these 50 people who like none of the three drinks.
Model Answer — (a)(i)
Start at the centre: 6. Then T ∩ C only = 14 − 6 = 8, T ∩ J only = 13 − 6 = 7, C ∩ J only = 11 − 6 = 5   M1
T only = 31 − 8 − 7 − 6 = 10, C only = 26 − 8 − 5 − 6 = 7, J only = 23 − 7 − 5 − 6 = 5   M1
10 + 7 + 5 + 8 + 7 + 5 + 6 = 48 like at least one, so 2 like none   A1
Second route: 31 + 26 + 23 − 14 − 13 − 11 + 6 = 48, then 50 − 48 = 2. ✓
⚠ If you missed marks here: the answer is not 50 and it is not 6. Two things go wrong here. The first is subtracting overlaps only once — 31 + 26 + 23 counts anyone in two sets twice and anyone in all three three times, which is why the triple overlap has to be added back. The second is leaving the middle until last: always write the 6 in first, then take it off each pair, then take those off each single. Every number you were given is a total, not a region.
(a)(ii) [3]
Find the number of these 50 people who like exactly one of the three drinks.
Model Answer — (a)(ii)
"Exactly one" means the three outer regions only, not the overlaps   M1
T only = 10, C only = 7, J only = 5   M1 (all three correct, from part (a)(i))
10 + 7 + 5 = 22   A1
Check: 22 like exactly one, 8 + 7 + 5 = 20 like exactly two, 6 like all three, 2 like none, and 22 + 20 + 6 + 2 = 50. ✓
⚠ If you missed marks here: if you answered 48 you gave the number who like at least one, and if you answered 31 you read a set total straight off the question. "Exactly one" is three regions of the diagram added together — the crescents, with every overlap stripped out. The safest habit is to fill in all eight regions before you answer anything, then just add the ones you need.
(b)(i) [2]
Write down, in set notation, the set of people who like tea and juice but do not like coffee.
Model Answer — (b)(i)
inside T, inside J, outside C   M1
T ∩ J ∩ C ′   A1
⚠ If you missed marks here: a union symbol here would be wrong: "tea and juice" is an intersection, and ∪ would mean people who like either one. The phrase "but do not" is always a complement, so it becomes C ′.
(b)(ii) [2]
For two different sets A and B ,
n( A ) = 3 x + 2 ,   n( B ) = 2 x + 7 ,   n( A ∩ B ) = x − 1 and   n( A ∪ B ) = 34 .
Find the value of x .
Model Answer — (b)(ii)
n( A ∪ B ) = n( A ) + n( B ) − n( A ∩ B )
(3 x + 2) + (2 x + 7) − ( x − 1) = 4 x + 10   M1
4 x + 10 = 34, so 4 x = 24 and x = 6   A1
Check: n( A ) = 20, n( B ) = 19, n( A ∩ B ) = 5, and 20 + 19 − 5 = 34. ✓
⚠ If you missed marks here: the sign error is the whole question: subtracting the bracket means both terms change sign, so −( x − 1) is − x + 1, not − x − 1. Getting −1 there gives 4 x + 8 = 34 and a fraction, which is a signal you have dropped a sign rather than that the question is unfair. Put the bracket in, then expand.
Question 2 — Percentages
Total: 10 marks
(a) [3]
40 kg of an alloy containing 60% copper is mixed with 60 kg of a different alloy containing 35% copper.
Calculate the percentage of copper in the mixture.
Model Answer — (a)
copper from the first alloy = 60% of 40 = 24 kg   M1
copper from the second = 35% of 60 = 21 kg, so there is 45 kg of copper   M1
total mass = 40 + 60 = 100 kg, so the mixture is 45 ÷ 100 = 45% copper   A1
⚠ If you missed marks here: averaging the two percentages gives 47.5% and is wrong, because there is more of the weaker alloy — 60 kg against 40 kg — so the answer must be pulled below the halfway point. A percentage of one quantity cannot be added to a percentage of a different quantity. Turn both into real kilograms of copper first, then divide by the real total mass.
Information for the whole question
A repair bill comes to $153 in total.
The bill is made up of parts and labour.
Sales tax of 20% is charged on the parts, but no sales tax is charged on the labour, which costs $45.
(b)(i) [3]
Calculate the cost of the parts before sales tax is added.
Model Answer — (b)(i)
the labour is untaxed, so the taxed portion of the bill is 153 − 45 = $108   M1
$108 is the parts after a 20% increase, so it is 120% of the parts: 108 ÷ 1.2   M1
parts = $90   A1
Check forwards: 90 × 1.2 = 108, and 108 + 45 = 153. ✓
⚠ If you missed marks here: dividing the whole $153 by 1.2 gives $127.50 and is the standard error — it quietly taxes the labour, which the question says is untaxed. Strip out every untaxed item before you reverse the percentage. And 108 ÷ 1.2 is a division, not "take off 20%": taking 20% off 108 gives 86.40, which does not grow back to 108.
(b)(ii) [1]
Write down how much of the $153 bill is sales tax.
Model Answer — (b)(ii)
108 − 90 = $18   B1
Check: 20% of 90 = $18, and 90 + 18 + 45 = 153. ✓
⚠ If you missed marks here: the tax is 20% of the parts, not 20% of the whole bill — 20% of 153 is $30.60, which would leave the arithmetic not adding up. If your three figures do not sum back to the total on the bill, one of them is wrong.
(c)(i) [2]
Tanvi scored 33 out of 40 in one test and 45 out of 60 in another test.
Express each score as a percentage.
Model Answer — (c)(i)
33 ÷ 40 = 0.825, and 0.825 × 100 = 82.5%   M1
45 ÷ 60 = 0.75, so 75%
82.5% and 75%   A1
⚠ If you missed marks here: the two tests are out of different totals, which is exactly why raw scores cannot be compared — 45 is a bigger number than 33 and yet it is the weaker result. Without a calculator, 33 ÷ 40 is easiest as 33 ÷ 4 = 8.25 then × 10, or as ¼ of 33 × 10.
(c)(ii) [1]
Find the difference between the two percentages.
Model Answer — (c)(ii)
82.5 − 75 = 7.5 percentage points   B1
⚠ If you missed marks here: the difference between two percentages is measured in percentage points, not in per cent. Saying "7.5% better" means something different and is wrong here: as a percentage increase from 75 it would be 7.5 ÷ 75 = 10%. Cambridge accepts 7.5 either way in this part, but the distinction is worth having — it changes the answer whenever a question asks for a percentage increase.
Question 3 — Time
Total: 10 marks
(a)(i) [2]
Bakary works a night shift. It starts at 21:48 and ends at 06:15 the next morning.
Find the length of the shift, in hours and minutes.
Model Answer — (a)(i)
21:48 → midnight is 2 h 12 min, and midnight → 06:15 is 6 h 15 min   M1
2 h 12 + 6 h 15 = 8 h 27, so the shift lasts 8 hours 27 minutes   A1
In minutes: 06:15 the next day is 1440 + 375 = 1815, and 21:48 is 1308, and 1815 − 1308 = 507 = 8 h 27 min. ✓
⚠ If you missed marks here: subtracting 21:48 from 06:15 straight down the page gives a negative answer, and "15 h 33" comes from doing it the wrong way round (21:48 − 06:15). When a time crosses midnight, split it at midnight and add the two pieces, or add 24 hours to the finishing time before you subtract. Never column-subtract: 15 − 48 is not 33 on a clock.
(a)(ii) [3]
During each shift Bakary takes a break of 45 minutes, which is not counted as working time.
Find the total working time in 5 of these shifts.
Give your answer in hours and minutes.
Model Answer — (a)(ii)
working time in one shift = 8 h 27 min − 45 min = 7 h 42 min   M1
5 × 7 h 42 min: 5 × 7 h = 35 h and 5 × 42 min = 210 min = 3 h 30 min   M1
35 h + 3 h 30 min = 38 hours 30 minutes   A1
In minutes: 507 − 45 = 462, and 462 × 5 = 2310 = 38 h 30 min. ✓
⚠ If you missed marks here: two base-60 traps again. Taking 45 minutes off 8 h 27 needs a borrow, so it is 7 h 42 — not 8 h 18 and not 7 h 82. Then 5 × 42 = 210 minutes, which is 3 h 30, not "2 h 10". Minutes only convert to hours in sixties. If you find yourself writing a minutes figure of 60 or more, convert it before you go any further.
Information for the whole question
The timetable shows four sailings from Northcliff to Ardmore.
The times are given using the 12-hour clock. A time shown as 12.25 am is in the early hours of the following day.
SailingDepart NorthcliffArrive Ardmore
S16.45 am8.20 am
S211.55 am1.35 pm
S32.10 pm3.40 pm
S410.40 pm12.25 am
(b)(i) [2]
Write down the departure time and the arrival time of sailing S2, using the 24-hour clock.
Model Answer — (b)(i)
11.55 am is before noon, so it stays as 11:55   B1
1.35 pm is after noon, so add 12 hours to the hours: 1 + 12 = 13, giving 13:35
11:55 and 13:35   B1
⚠ If you missed marks here: writing 01:35 is the error to avoid — that is twenty-five to two in the morning. In the 24-hour clock a pm time has 12 added to the hours (1 pm is 13:00, 11 pm is 23:00), an am time keeps its hours, and the two exceptions are 12 midnight, which is 00:00, and 12 noon, which is 12:00. Take both times from the S2 row and nowhere else.
(b)(ii) [3]
Find how much longer the slowest sailing takes than the fastest sailing.
You must show the time taken by each sailing.
Model Answer — (b)(ii)
S1: 6.45 am → 8.20 am = 1 h 35 min = 95 min  ·  S2: 11:55 → 13:35 = 100 min   M1
S3: 14:10 → 15:40 = 90 min  ·  S4: 22:40 → 00:25 the next day = 1 h 45 min = 105 min   M1
slowest is S4 at 105 min, fastest is S3 at 90 min, difference = 15 minutes   A1
⚠ If you missed marks here: S4 is the one that decides this question and it is the one most likely to be wrong, because it finishes after midnight — 12.25 am is 00:25 on the next day, so it is 1 h 45 min, not a negative answer and not 10 h 15. And you cannot tell which crossing is slowest by looking at the table; all four have to be worked out. Convert every time to the 24-hour clock first, then subtract, and treat a crossing that passes midnight by splitting it there.
Question 4 — Money and finance
Total: 10 marks
(a)(i) [3]
Mei invests £5000 for 2 years at r % per year compound interest.
At the end of the 2 years her investment is worth £5408.
Find the value of r .
Model Answer — (a)(i)
let the yearly multiplier be k , so 5000 k ² = 5408 and k ² = 1.0816   M1
104² = 10816, so √1.0816 = 1.04 and the multiplier is 1.04   M1
r = 4%   A1
Trial route, which needs no square root: 5000 × 1.04 = 5200, and 5200 × 1.04 = 5408. ✓
⚠ If you missed marks here: treating this as simple interest gives 408 ÷ 2 = 204 a year and r = 4.08%, which is close enough to look right and is wrong — with compound interest the second year earns more than the first, so the rate must be below the simple-interest answer. Two years of compound interest multiply by k ², so finding k means taking a square root; on a non-calculator paper that root is always exact, and here 1.0816 comes from 104² = 10816. If you cannot spot the root, try 4% and 5% and check.
(a)(ii) [1]
Find the interest earned during the second year only.
Model Answer — (a)(ii)
after 1 year: 5000 × 1.04 = £5200, so the second year earns 5408 − 5200 = £208   B1
⚠ If you missed marks here: answering £204 means you halved the total interest of £408, which is what simple interest would do. Under compound interest the second year earns interest on £5200, not on £5000, so it must be more than the first year’s £200. A second-year figure smaller than the first year’s is always a signal that something has gone wrong.
(b) [3]
A shop buys an item for $60.
It sells the item at a price that gives a profit of 25% of the selling price.
Calculate the selling price.
Model Answer — (b)
the profit is 25% of the selling price, so the $60 cost is the other 75% of it   M1
selling price = 60 ÷ 0.75   M1 (or 75% → 60, so 25% → 20 and 100% → 80)
$80   A1
Check: profit = 80 − 60 = $20, and 20 ÷ 80 = 0.25. ✓
⚠ If you missed marks here: the trap is answering $75 by adding 25% to the cost. Read which number the percentage is of: almost every profit question on this course measures profit against the cost, and this one deliberately measures it against the selling price, so the 100% you are working towards is the selling price and not the $60. Check your answer by computing the profit as a fraction of the price you found — with $75 you would get 15 ÷ 75 = 20%, not 25%.
Information for the whole question
Rafael’s income is $2400 each month.
He spends 35% of his income on rent.
He spends a quarter of what is left on food.
He saves the rest.
(c)(i) [2]
Calculate the amount Rafael saves each month.
Model Answer — (c)(i)
rent = 35% of 2400 = $840, so $1560 is left   M1
food = ¼ of 1560 = $390, so he saves 1560 − 390 = $1170   A1
Check: 840 + 390 + 1170 = $2400. ✓
⚠ If you missed marks here: the phrase that decides this question is what is left. A quarter of his income would be $600, but he spends a quarter of the $1560 that survives the rent, which is $390. Percentages and fractions in a chain each apply to whatever is left at that moment, not to the original amount — unless the question says otherwise. Adding your three figures back to $2400 catches this instantly.
(c)(ii) [1]
Express the amount he saves as a percentage of his income.
Model Answer — (c)(ii)
1170 ÷ 2400 = 0.4875, so he saves 48.75% of his income   B1
Check: 48.75% + 35% (rent) + 16.25% (food) = 100%. ✓
⚠ If you missed marks here: divide by the income, $2400, and not by the $1560 that was left after the rent — that would give 75%, which is the fraction of the remainder he saves, a different quantity. The question names the total it wants the percentage taken of; underline it before dividing.

Self-Assessment

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