The equation for the combustion of hydrogen is:
2H₂(g) + O₂(g) → 2H₂O(g)
Use the bond energy data below to calculate the enthalpy change (ΔH) for this reaction.
| Bond | Bond energy / kJ mol⁻¹ |
| H–H | 436 |
| O=O | 498 |
| O–H | 464 |
Show all your working.
Model Answer -- 4(b)
Bonds broken: 2 × H–H + 1 × O=O = (2 × 436) + (1 × 498) = 872 + 498 = 1370 kJ [1]
Bonds formed: 4 × O–H (two water molecules, each with 2 O–H bonds) = 4 × 464 = 1856 kJ [1]
ΔH = energy of bonds broken − energy of bonds formed [1]
ΔH = 1370 − 1856 = −486 kJ mol⁻¹ [1]
The negative sign indicates the reaction is exothermic [1]